The right way to Discover the Index of the Minimal Aspect in a Checklist in Python

If you could discover the index of the minimal factor in an inventory, you are able to do one of many following:

Possibility 1 – Utilizing min() and index()

lst = [8,6,9,-1,2,0]
m = min(lst)
print(lst.index(m))

Output: 3

Possibility 2 – Utilizing min() and for

lst = [8,6,9,-1,2,0]
m = min(lst)
for i in vary(len(lst)):
    if(lst[i]==m):
        print(i)
        break

Output: 3

Possibility 3 – Utilizing min() and enumerate()

lst = [8,6,9,-1,2,0]
a,i = min((a,i) for (i,a) in enumerate(lst))
print(i)

Output: 3

Possibility 4 – Utilizing min() and operator.itemgetter()

from operator import itemgetter
lst = [8,6,9,-1,2,0]
i = min(enumerate(lst), key=itemgetter(1))[0]
print(i)

Output: 3

Possibility 5 – Utilizing numpy.argmin()

import numpy as np
lst = [8,6,9,-1,2,0]
i = np.argmin(lst)
print(i)

Output: 3